Question

It is given that ph of a solution a is 3 and it is mixed with an equal volume of another solution b having ph 2. If both are mixed, then resultant ph of the solution will be

Answer 1

Answer:

Explanation: ph =3= 10-3

Ph=2=10-2

Equal volumes

(H+)= v 10-3+10-2v/2v

H+= 5.5*10-3

Ph=-log H+

Ph = 3-log5.5

Ph=3-0.74

Ph=2.26

Answer 2

Answer: 2.26

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

1. pH = 3

$pH=-\log [H^+]$

$3=-\log[H^+]$

$[H^+]=10^{-3}$

2. pH = 2

$pH=-\log [H^+]$

$2=-\log[H^+]$

$[H^+]=10^{-2}$

Suppose both solutions are taken to be 1 L each, thus concentration of resultant solution will be:

$[H^+]=\frac{10^{-3}+10^{-2}}{2L}=0.0055M$

Thus $pH=-log[H^=]=-log[0.0055]=2.26$

Thus If both are mixed, then resultant ph of the solution will be 2.26.