Question

It is given that the events A and B are such that P(A) = $\frac{1}{4}$, P(A | B) = $\frac{1}{2}$ and P(B | A) = $\frac{2}{3}$. Then P(B) is
(a) $\frac{1}{6}$
(b) $\frac{1}{3}$
(c) $\frac{2}{3}$
(d) $\frac{1}{2}$

Answer 1

Hello mate ☺

Option B is correct one

Hope it helps u...❤

Answer 2

It is given that the events A and B are such that P(A) = $\frac{1}{4}$, P(A | B) = $\frac{1}{2}$ and P(B | A) = $\frac{2}{3}$. Then P(B) is

(a) $\frac{1}{6}$

(b) $\frac{1}{3}$✔

(c) $\frac{2}{3}$

(d) $\frac{1}{2}$