Question

It is given that the specific heat of copper is one tenth that of water

Answer 1

Answer:

given Cp of copper ( =1 / 10^{*} ) Cp of water let T be the final temperature ( 100 mathrm{cc} ) of water ( =100 mathrm{g} ) heat rejected by copper = heat absorbed by water ( 100^{*}(1 / 10)^{*}(200-T)=100^{*}(T-24) ) ( 20-(T / 10)=T-24 ) ( 44=left(11^{*} T / 10right) ) ( T=44^{*} 10 / 11=40^{circ} mathrm{C} )