it is given that , The third term of the arthmetic progression is 15 , sum of the 10 terms of arthmetic progression is 125 and number of terms are 10 . find the common difference and 10th term of arthmetic progression ?
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D=-10
T10=-65
15=a+2d
125=10÷2(2(15-2d)+9d)
D=-10
15=a+2*(-10)
a=25
Now
T10=25+9d
=-65
T10=-65
15=a+2d
125=10÷2(2(15-2d)+9d)
D=-10
15=a+2*(-10)
a=25
Now
T10=25+9d
=-65
srujan333:
its wrong . but thank you for response
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0
very good question very intereating
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some where you did it mistake ... the answers is not correct as compared to my text book . but thank you. I hope you will correct it and send to me again a correct answer.
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