Question

Mother's age is thrice the age of Amar and Amar's age is one year more than the twice age of Sanika. If sum of their ages is 49 years, what is the mother's age ?

Answer 1

let sanika age be x
then amar s age is 2x+1
then mothers age is 6x +3
x+2x+1+6x+3=49
9x+4=49
9x=45
×=45/9
x=5
there fore
sanika age is 5
amar s age is 11
mother s age is 33

Answer 2

hi 
let the age of sanika = x 
then age of amar = 2x + 1 
then  age of mother = 3(2x + 1)= 6x+3 
sum of all the ages = 49 =  x +  2x+1  6x+3
                                  49 = 9x + 4 
                                   49 - 4 = 9x 
                                       45/9 = x
                                        5 = x 
now age of the mother = 6x + 3 
                                        = 6 x 5+ 3 
                                           = 30 + 3 
                                              = 33

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