Question

it is given that triangke abc similar to triangle def abd bc/ef =1/5 then area of abc / area of def will be​

Answer 1

Answer:

Solution

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(i) Consider the quadrilateral ABED

We have , AB=DE and AB∥DE

One pair of opposite sides are equal and parallel. Therefore

ABED is a parallelogram.

(ii) In quadrilateral BEFC , we have

BC=EF and BC∥EF. One pair of opposite sides are equal and parallel.therefore ,BEFC is a parallelogram.

(iii) AD=BE and AD∥BE ∣ As ABED is a ||gm ... (1)

and CF=BE and CF∥BE ∣ As BEFC is a ||gm ... (2)

From (1) and (2), it can be inferred

AD=CF and AD∥CF

(iv) AD=CF and AD∥CF

One pair of opposite sides are equal and parallel

⇒ ACFD is a parallelogram.

(v) Since ACFD is parallelogram.

AC=DF ∣ As Opposite sides of a|| gm ACFD

(vi) In triangles ABC and DEF, we have

AB=DE ∣ (opposite sides of ABED

BC=EF ∣ (Opposite sides of BEFC

and CA=FD ∣ Opposite. sides of ACFD

Using SSS criterion of congruence,

△ABC≅△DEF