it is given that triangle ABC is congruent to triangle DFE . If <A = 30 <C =50 AB = 5 and AC = 8 and if is DF=7.5 then which of the following is true.
A. DE = 12cm , <F = 50°
B) DE = 12cm , <F = 100°
C) EF = 12cm , <D = 100°
D) EF = 12cm , <D = 30°.
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(b) DE = 12cm, ∠F = 1000
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Answer:
Given: ∆ABC ∼ ∆DFE,
As ∆ABC ∼ ∆DFE
so, by the property of Corresponding angles of similar triangles,
We have, ∠A = ∠D = 30° (Corresponding angles) ∠C = ∠E = 50° (Corresponding angles)
We know that sum of angles of a triangle = 180° So, ∴ ∠B = ∠F = 180°- (30° + 50°) = 100°
Also Given, AB = 5 cm, AC = 8 cm and DF = 7.5 cm
Hence, DE = 12 cm, and ∠F = 100
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