Question

it is given that triangle ABC is similar to triangle pqr and BC by QR is equal to 2 by 3 then find area of triangle PQR by area of triangle ABC​

Answer 1

Its given that triangle ABC is similar to the triangle PQR

so

${ \frac{rq}{bc} }^{2} = \frac{pqr}{abc}$

there fore square of3/2 =9/4

pqr/abc=9/4

hope it will help you

Answer 2

Answer:

9/4

Step-by-step explanation:

Given:-

ΔABC ~ ΔPQR

∴AB/PQ = BC/QR = AC/PR

BC/QR = 2/3

To find:-

ar(ΔPQR) / ar(ΔABC)

Solution:-

BC/QR = 2/3

∴ QR/BC = 3/2

∴ar(ΔPQR) / ar(ΔABC) = (QR / BC)²

=(3/2)²

= 9 / 4

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