Question

it is given that triangle abc similar triangle pqr with bc/qr=1/3. find the ratio of ar(PRQ)/ar(BCA).

Answer 1

Hello,

Here is your answer,

Given BC/QR = 1/3

We know the ratio of areas of similar triangles is equal to the square of the ratio of their corresponding sides.

Thus ar(∆ABC)/ar(∆PQR) = (BC/QR)²

=> ar(∆ABC)/ar(∆PQR) = (1/3)²

=> ar(∆ABC)/ar(∆PQR) = (1/9)

Hope this helps

Answer 2

hope this helps you...