it is given that xyz =54 and xy is produced to point p y yq bisect zyp find xyq and reflex qyp
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Answer:
6th
Maths
Understanding Elementary Shapes
Types of Angles
It is given that XYZ = 64 ...
MATHS
It is given that ∠XYZ=64
and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ∠ZYP, find ∠XYQ and reflex ∠QYP.
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ANSWER
Given,
∠XYZ=64
∘
YQ bisects ∠ZYP
∠XYZ+∠ZYP=180
∘
(Linear Pair)
⇒64
∘
+∠ZYP=180
∘
∠ZYP=116
∘
Also, ∠ZYP=∠ZYQ+∠QYP
∠ZYQ=∠QYP (YQ bisects∠ZYP)
⇒∠ZYP=2∠ZYQ
⇒2∠ZYQ=116
∘
⇒∠ZYQ=58
∘
=∠QYP
Now, ∠XYQ=∠XYZ+∠ZYQ
⇒∠XYQ=64
∘
+58
∘
⇒∠XYQ=122
∘
Also, reflex ∠QYP=180
∘
+∠XYQ
∠QYP=180
∘
+122
∘
⇒∠QYP=302
∘
solution
Question :-
It is given that ∠XYZ = 64° and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ∠ZYP, find ∠XYQ and reflex ∠QYP.
Answer :-
i.e : XYP is a straight line.
∴ ∠XYZ + ∠ZYQ + ∠QYP = 180°
⇒ 64° + ∠ZYQ + ∠QYP = 180°
[∵ ∠XYZ = 64° (given)]
⇒ 64° + 2∠QYP = 180°
[YQ bisects ∠ZYP so, ∠QYP = ∠ZYQ]
⇒ 2∠QYP = 180° – 64° = 116°
⇒ ∠QYP = 116°/2 = 58°
∴ Reflex ∠QYP = 360° – 58° = 302°
Since ∠XYQ = ∠XYZ + ∠ZYQ
⇒ ∠XYQ = 64° + ∠QYP [∵∠XYZ = 64°(Given) and ∠ZYQ = ∠QYP]
⇒ ∠XYQ = 64° + 58° = 122° [∠QYP = 58°]
Thus, ∠XYQ = 122° and reflex ∠QYP = 302°.
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