It is given that ∠ XYZ = 64° and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ∠ ZYP, find ∠ XYQ and reflex ∠ QYP.
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Given: ∠XYZ = 64°
Now, ∠XYZ + ∠ZYP = 180°(Linear pair)
Or, 64° + ∠ZYP = 180°
Or, ∠ZYP = 180° - 64° = 116°
Since, YQ bisects ∠ZYP
So, ∠ZYQ = ∠PYQ = ½ ∠ZYP = 116°/2 = 58°
So, ∠XYQ = ∠XYZ + ∠ZYQ = 64°+ 58° = 122°
Now, reflex ∠QYP = 360° - 58° = 302°
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It is given that,
∠XYZ = 64°
As, ∠XYZ + ∠ZYP = 180°(Linear pair)
64° + ∠ZYP = 180°
∠ZYP = 180° - 64° = 116°
As, YQ bisects ∠ZYP
Therefore, ∠ZYQ = ∠PYQ = ½ ∠ZYP
= 116°/2
= 58°
Therefore, ∠XYQ = ∠XYZ + ∠ZYQ
= 64°+ 58°
= 122°
Therefore, reflex of ∠QYP
= 360°- 58°
= 302°
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