Question

It is given that Z XYZ = 64° and XY is produced
to point P. Draw a figure from the given
information. If ray YQ bisects Z ZYP, find Z XYQ
and reflex ZQYP.​

Answer 1

XYP is a straight line

∠xyz + ∠XYP = 180°

∠xyp = 180 -∠xyz

∠xyp = 180° - 64°

∠xyp = 116 °

Since , YQ bisects ∠Xyp =

∠ xyq = ∠Qyp = 1/2 ∠xyp

=1/2 ×116

= 58°

Please check the attachment .

@badshah

Tere haaath jod Raha hu branliest mark karde please !!!

Answer 2

Question :-

It is given that ∠XYZ = 64° and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ∠ZYP, find ∠XYQ and reflex ∠QYP.

Answer :-

i.e : XYP is a straight line.

∴ ∠XYZ + ∠ZYQ + ∠QYP = 180°

⇒ 64° + ∠ZYQ + ∠QYP = 180°

[∵ ∠XYZ = 64° (given)]

⇒ 64° + 2∠QYP = 180°

[YQ bisects ∠ZYP so, ∠QYP = ∠ZYQ]

⇒ 2∠QYP = 180° – 64° = 116°

⇒ ∠QYP = 116°/2 = 58°

∴ Reflex ∠QYP = 360° – 58° = 302°

Since ∠XYQ = ∠XYZ + ∠ZYQ

⇒ ∠XYQ = 64° + ∠QYP [∵∠XYZ = 64°(Given) and ∠ZYQ = ∠QYP]

⇒ ∠XYQ = 64° + 58° = 122° [∠QYP = 58°]

Thus, ∠XYQ = 122° and reflex ∠QYP = 302°.

Plz mrk as brainliest ❤