Question

It is known that in the sequence A, X, B, C, D, Y, 11 the sum of any three consecutive
terms is 19. Find the value of A + B + C + D

Answer 1

Answer:

30

Step-by-step explanation:

D+Y+11=19 Gives D+Y=8

Again C+D+Y=19 gives C=8

Now X+B+C=19 Gives X+B=8

From A+X+B=19 We get A=11

Now B+C+D=19 and A=11 then the required value is 30