Question

It is onbserved that a projectile is at the same height at 3s and 5s from the start the time of flight of projectile equal to​

Answer 1

Given :

Projectile is at the same height at 3s and 5s from the start..

To Find :

We have to find time of flight..

Solution :

➠ There are two values of time for which the projectile is at the same height. The sum of these two times is equal to the time of flight.

➝ T = t¹ + t²

➝ T = 3 + 5

➝ T = 8 s

Learn More :

• A body is said to be projectile if it is projected into space with some initial velocity and then it continues to move in a vertical plane such that its horizontal acceleration is zero and vertical downward acceleration is equal to g.
• In projectile motion, the horizontal motion and the vertical motion are independent of each other.

Answer 2

Answer:

The required time of flight is found to be 8 seconds.

Step-by-step explanation:

Projectile Motion:

A projectile is an object that is thrown into space and is affected only by gravity. The main force acting on the projectile is gravity. This does not necessarily mean that there are no other forces at work, just that their influence is minimal compared to gravity. The path taken by a projectile is called its trajectory. Baseball batting and throwing are examples of projectiles.

Calculation of time of flight:

Now, we are given the time taken during the projectile to go from one point to another (of same height) is: 5s - 3s = 2s,

Now, we can say that the time taken by the object to reach from one point considered above to the highest point of the projectile will be: $\frac{2}{2}$ = 1s,

Now, the time taken from the starting point to the highest point of the projectile will be: 0s + 3s + 1s = 4s

Hence, the total time of flight will be the double of this time, i.e.,: 8 seconds.

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