Question

it is raining at a speed of 5ms-one at angle 37° to vertical ,towards east .A man is moving to west with a velocity of 5ms-one .the angle with the vertical at which he has to hold the umbrella to product to protect himself from rain is ​

Answer 1

$\huge{\underline{\tt{\red{Answer-}}}}$

$tan-1\ (2) to \ west$

$\huge{\underline{\tt{\blue{Explanation-}}}}$

$sin 37\textdegree = \dfrac{x}{v_r} = \dfrac{3}{5}$

$cos 37\textdegree= \dfrac{y}{v_r}$

$tan \theta = \dfrac{x+v_m}{y}$

$tan \theta = \dfrac{5+3}{4} =\dfrac{8}{4}= 2$

$\theta = tan-1\ (2) to \ west$

__Refer the attachment plzz___

Answer 2

explanation:

Given:theta is 37 degrees

1. sin37=x/vR=3/5
2. cos37=y/vR
3. So,

tan(theta)=x+vM/y

=3+5/ 4

=8/4

2

1. so, theta=tan-1(2)to west

HOPE IT HELPS YOU