Question

Please answer this question:-​

Answer 1

Answer:

70°

Step-by-step explanation:

In Parallelogram MNOP,

MPO = MNO

MPO=60°

In ||gm ABCD,

ADC + DCB =180°

130 + DCB =180°

DCB =50°

In ∆PQC,

60° +50°+x=180°

x= 70°

Thanks

Answer 2

Answer:

Step-by-step explanation:

∠D=∠B=130° (Opposite angles in parallelogram are equal)

∠D+∠A=180° (Adjacent angles in parallelogram are supplementary)

130+A=180

A=180-130

A=50°

∠A=∠C=50°

∠N=∠P=60° (Opposite.....equal)

∠N+∠O=180° (Adjacent......equal)

60+O=180

O=180-60

O=120°

Now, PQC is a triangle

∠P+∠Q+∠C=180

60+50+x=180

110+x=180

x=180-110

x=70°