it is required to increase the speed of a scooter weight 80 kg from 5 metre per second 25 m per second in 2 sec what is the force required
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Answered by
8
F = ma (m-mass, a- acceleration)
So m=80kg, we have to now find out a for getting the force.
So the change in speed(∆v) is 25–5m/s=20m/s and this event took place in 2 sec so a=∆v/∆t
So now we get ∆v/∆t=20/2=10ms²
Therefore m=80kg and a=10ms²
F=80×10=800 Newton(N).
Hope it helps you
Please make me as brainliest
So m=80kg, we have to now find out a for getting the force.
So the change in speed(∆v) is 25–5m/s=20m/s and this event took place in 2 sec so a=∆v/∆t
So now we get ∆v/∆t=20/2=10ms²
Therefore m=80kg and a=10ms²
F=80×10=800 Newton(N).
Hope it helps you
Please make me as brainliest
navadeep7:
please make me as brainliest
Answered by
17
mass (m) =80kg
initial velocity (u) = 5m/s
final velocity (v) = 25m/s
time(t)= 2s
force(F)= ma
F= m (v-u) /t
F= 80*(25-5)/2
F= 80* 10
F= 800N
hope it helps
please mark brainliest
initial velocity (u) = 5m/s
final velocity (v) = 25m/s
time(t)= 2s
force(F)= ma
F= m (v-u) /t
F= 80*(25-5)/2
F= 80* 10
F= 800N
hope it helps
please mark brainliest
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