Question

it is required to increase the velocity of a scooter of mass 80kg from 6 to25ms-1in 2 second. calculate the force required​

Answer 1

Explanation:

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Answer 2

Given:-

☛scooter of mass = 80 kg

☛Initial velocity = 6m/s

☛Final velocity = 25m/s

☛Time taken = 2 sec

 

Find:-

☛Force -?

Formula to be used :-

☛ $\boxed{\sf{F=ma}}$

☛ $\boxed{\bf{ v=u+at}}$

Where,

F=force

m= mass

a= acceleration

v= final velocity

u= initial velocity

t=time taken

Solution:-

Using 1st equation of motion,

$\bf{ v=u+at}$

Put values,

$\sf{\implies 25= 6+ a \times 2}$

$\sf{\implies 25-6=a \times 2}$

$\sf{\implies a= \dfrac{19}{2} = 9.5 }$

Acceleration = 9.5 m/s²

 

Now According to 2nd law of motion,

$\sf{ F= ma}$

Put values,

$\sf{\implies F= 80 \times 9.5 }$

$\sf{\implies F= 80 \times \dfrac{95}{10} }$

$\sf{ \implies F= 8\times 95}$

$\sf{\implies F=760 N}$

 

Therefore, Force required is 760N.