it is urgent please answer fast
Attachments:
Answers
Answered by
1
Area of ||gm = b×h
200 = 25h
h = 200/25 = 8cm
In ∆ADE
AD² = DE² + AE² (P.G.T)
17² = 8² + AE²
289 = 64 + AE²
AE = √289 - 64 = 15cm ...done
Now, AB = 25cm (given)
EB = 25-15 = 10cm
200 = 25h
h = 200/25 = 8cm
In ∆ADE
AD² = DE² + AE² (P.G.T)
17² = 8² + AE²
289 = 64 + AE²
AE = √289 - 64 = 15cm ...done
Now, AB = 25cm (given)
EB = 25-15 = 10cm
Similar questions