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Given:AE=25cm
AD=17cm
Area=200cm
Solution:
Area of a parallelogram:base×altitude
200=AB×DE
200=25×DE
DE=200/25
DE=8cm
According to Pythagoras theorem
(AD)^2=(AE)^2+(DE)^2
17^2=(AE)^2+8^2
289=(AE)^2+64
(AE)^2=289-64
AE=√225
AE=15cm
AB=AE+EB
25=15+EB
EB=25-15=10cm
Thus, AE=15cm
EB=10cm
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