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4x²-6x-28
4x²-14x+8x-28
2x(2x-7)+4(2x-7)
(2x-7)(2x+4) ans
4x²-14x+8x-28
2x(2x-7)+4(2x-7)
(2x-7)(2x+4) ans
how u take 14
plz tell me
but you find answer 2x+7,2x-4but real ans is 2x-7,2x+4
ok ...im waiting for u ans
sry ans is not showing
Answered by
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By splitting the middle term
we have to split middle term that is 6x in such way so that thier difference would be 6 and their product would be the product of 1st and last term i.e, 4 and 28
=>. 4x²-(14-8)x-28
=4x²-14x+8x-28
Taking common
2x(2x-7)+4(2x-7)
=>(2x-7)(2x+4)
Hope it will help you.
we have to split middle term that is 6x in such way so that thier difference would be 6 and their product would be the product of 1st and last term i.e, 4 and 28
=>. 4x²-(14-8)x-28
=4x²-14x+8x-28
Taking common
2x(2x-7)+4(2x-7)
=>(2x-7)(2x+4)
Hope it will help you.
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