Question

It one of the zeroes of the polynomial
$3y ^{2} + 13y - p$
is the reciprocal of the other ,find p ?
POLYNONOMIAL-2 CLASS 10​

Answer 1

Answer:

p = 3

Step-by-step explanation:

Given a quadratic polynomial such that,

3y^2 + 13y - p

Let's make it a quadratic equation.

For this, we will equate this to zero.

Therefore, we will get,

=> 3y^2 + 13y - p = 0

Also, given that,

It's zeroes are reciprocal of each other.

Let, one of the zero is x.

Therefore, another one will be 1/x.

Now, to find the value of p.

We know that,

Product if zereos = c/a .

Here, we have,

• a = 3
• b = 13
• c = p

Therefore, we will get,

=> x × 1/x = p/3

=> p/3 = 1

=> p = 3

Hence, required value of p = 3.

Answer 2

P = 3

HERE IS UR ANSWER..HELP YOU LIKE IT