Question

it rain started journey from station p accelerated at the rate of 2 metre per second square and reaches its maximum speed in 10 second it maintains this is paid for 30 minute and retired uniformly tourist at the station q after the next 20 second calculate the maximum speed of train

Answer 1

v = u+at

v = 0+20       (It Starts From Rest)

v = 20m/s

1) Answer- 20m/s

a = v-u/t

a = 0-20/20

a = -1m/s^2

2) Answer-  -1m/s^2

Distance = Speed*Time

1st Case=  25*900 = 22500m 

Or 22.5 Km

Now 2Nd Case 

s = ut+1/2at^2

s = 25*20+1/2(-1*20*20)

s = 500-200

Or 300 m

Total Distance = 22500+300 = 22800m

But We Are Forgetting One Thing 

It Started From Rest It Attained Its Maximum Speed in 10 seconds so it should cover some distance in that period

s = ut+1/2at^2

s = 0+1/2*2*10*10

s = 100m

Total Distance = 22800+100 = 22900m Or 22.9 Km