It's a question from last year UPSC AC question: If A is coded as 1, B as 3, C as 5 and so on what is the numerical value of the word 'FAZED' if the numerical value of 'CABLE' is 41?
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A=1
B=3
C=5
The number increase by 2 (the difference is 2) so...
D=5+2=7
E=7+2=9
F=9+2=11
the general formula will be
a+(n-1)*difference.
F A Z E D
F=9
A=1
Z is the 26 th letter, and has the value
1+(26-1)*2=51
E=9
D=7
The sum will be
9+1+51+9+7=
10+60+7=
70+9=79
B=3
C=5
The number increase by 2 (the difference is 2) so...
D=5+2=7
E=7+2=9
F=9+2=11
the general formula will be
a+(n-1)*difference.
F A Z E D
F=9
A=1
Z is the 26 th letter, and has the value
1+(26-1)*2=51
E=9
D=7
The sum will be
9+1+51+9+7=
10+60+7=
70+9=79
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