Question

It’s chapter electricity class 10

Answer 1

Answer:

1833.3

Explanation:

1/Rp1 = 1/R1 + 1/R2 = 1/1 +1/10 = 11/10

               Rp1 = 10/11KΩ = 909Ω

1/Rp2 = 1/10 + 1/10 + 1/10 = 3/10

Rp2 = 10/3 kΩ = 333.3Ω

Rp3 = 0.5kΩ = 500 Ω

Req = 909 + 333.3 +500 + 91

      = 1833.3Ω