It's given that PQ || BA ; PR || CA. If PD = 12. Find BD ? CD.
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In triangle DPR. CQ parallel PR
Therefore. DC \CP= DQ \QR.............1
Similarly in triangle dbr.
DP\ PB=DQ\QR.,..............2
From 1&2
DC\CP=DP\PB
DC.PB=CP.DP
DC(BD-PD) = (PD-CD) DP
DC.BD-12CD=144-12CD
Therefore BD.CD =144
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