Question

it's is factorisation method
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Answer 1

$1. x^{2} + 6x + 5 = 0$

/* Splitting the middle term,we get */

$\implies x^{2} + 1x + 5x + 5 = 0$

$\implies x(x+1) + 5(x+1) = 0$

$\implies (x+1)(x+5) = 0$

$\implies x + 1 = 0 \:Or \: x + 5 = 0$

$\implies x = -1 \: Or \: x = - 5$

$2. x^{2} -5x + 6 = 0$

/* Splitting the middle term,we get */

$\implies x^{2} - 2x - 3x + 6= 0$

$\implies x(x-2) -3(x-2) = 0$

$\implies (x-2)(x-3) = 0$

$\implies x -2 = 0 \:Or \: x -3 = 0$

$\implies x = 2 \: Or \: x = 3$

$3. x^{2} -9x + 20= 0$

/* Splitting the middle term,we get */

$\implies x^{2} - 5x - 4x + 20= 0$

$\implies x(x-5) -4(x-5) = 0$

$\implies (x-5)(x-4) = 0$

$\implies x -5 = 0 \:Or \: x -4= 0$

$\implies x = 5 \: Or \: x = 4$

$4. x^{2} + 6x + 5 = 0$

/* Splitting the middle term,we get */

$\implies x^{2} + 1x + 5x + 5 = 0$

$\implies x(x+1) + 5(x+1) = 0$

$\implies (x+1)(x+5) = 0$

$\implies x + 1 = 0 \:Or \: x + 5 = 0$

$\implies x = -1 \: Or \: x = - 5$

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Answer 2

Here is ur ans hope it will helps u....

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