Question

ⓗⓔⓨ ⓕⓡⓘⓔⓝⓓⓢ ⓟⓛⓔⓐⓢⓔ ⓐⓝⓢⓦⓔⓡ


# it's of class 9

# Please don't spam

@ Prabhu dutt.....

Answer 1

Here's your answer....

Answer 2

$= > log_{10}x = a \\ \\ = > x = {e}^{a} \: \: \: \: \: \: ....[Eq _{1}]$
__________

$= > log_{10}y = b \\ \\ = > y = {e}^{b} \: \: \: \: ..[Eq _{2}]$
-__________

$= > log_{10}z = 2a - 3b \\ \\ = > z = {e}^{2a - 3b} \\ \\ = > z = {e}^{a} . {e}^{a} . {e}^{ - b} . {e}^{ - b} . {e}^{ - b} \\ \\ = > z = {e}^{a} . {e}^{a} . \frac{1}{ {e}^{b} } . \frac{1}{ {e}^{b} } . \frac{1}{ {e}^{b} } \: \: \: \: ...[Eq _{3}]$
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●PLUG THE VALUE OF Eq(1) AND Eq(2) TO IN Eq(3) :-

◢WE GET :-

$= > z = x.x. \frac{1}{y} . \frac{1}{y} . \frac{1}{y} = {x}^{2} . \frac{1}{ {y}^{3} } \\ \\ = > z = \frac{ {x}^{2} }{ {y}^{3} }$
___________________[◢ANSWER]

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