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question 16
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if we rolled rectangular paper along it's length to form a cylinder then in this case height of this particular cylinder will be equal to the breadth of the paper and the circumference of it's base will be equal to the length of the paper,
then
circumference of base=22 cm,
2πr=22,
2×22/7×r=22,
then
r=7/2 cm
therefore
volume of the cylinder =πr²h,
=22/7 × 7/2 × 7/2 × 12,
=11×7×6,
=462 cm³
then
circumference of base=22 cm,
2πr=22,
2×22/7×r=22,
then
r=7/2 cm
therefore
volume of the cylinder =πr²h,
=22/7 × 7/2 × 7/2 × 12,
=11×7×6,
=462 cm³
Shobhit1903:
thanks bro
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