It shows the motion of cyclists. Find a) acceleration b) the distance covered by a cyclists in 15 secs
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a = v- u / t
a = -20 / 15
a = -4/3 m / s ^2
s = ut + 1/2 at^2
s= 0×15 + -4/3 × 15 × 15
s = -300 m
as distance can not be in negative , therefore distance = 300 m
a = -20 / 15
a = -4/3 m / s ^2
s = ut + 1/2 at^2
s= 0×15 + -4/3 × 15 × 15
s = -300 m
as distance can not be in negative , therefore distance = 300 m
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