Physics, asked by lilyhaokip4180, 1 year ago

It takes 100J of work to stretch a spring 0.5m from its equilibrium position.How much work is needed to stretch it an additional 0.75m?

Answers

Answered by Vegota

1

work = 100 Joule

Displacement is 0.5 m

Therefore force equals to work by displacement

100 / 0.5

force is 200

therefore work done equals to force by displacement

200 / 0.75

266.66 Joule

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