It takes 15 min to rise the temperature of a certain amount of water from 00 C to boiling point using a
heater and it takes 1 hour and 20 minutes more to convert all water to vapor. Find the latent heat of
vaporization of the water. (6mks)
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ANSWER-:
Let the power delivered by the heater = P.
Heat supplied in 15 minutes = 15P = Q
Heat supplied in 1 hour and 20 minutes = 80P = Q
=mcΔT=m(1)(100)=100m
=mL L is the latent heat of vaporization.
i.e. dividing Q
and Q
80
15=L 100
i.e. L=533.33 cal.
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