Question

${x}^{4} - (y + z {)}^{4}$
factorise the above question.​

Answer 1

Answer:

$=(x + y + z)(x - y - z) [x {}^{2} + (y + z) {}^{2} ] \:$

Step- by -step Explanation:

$\\ Using \: the \: identity \: \\ a {}^{2} - b {}^{2} = (a + b)(a - b) \\ Therefore \: \: x {}^{4} - (y + z) {}^{4} \\ =( x {}^{2}) {}^{2} -[(y+z) {}^{2} ] {}^{2} \\ = [x {}^{2 } + (y + z) {}^{2} ] [x {}^{2} - (y + z) {}^{2} ] \\ We \: can \: factorise \: [x {}^{2} - (y + z) {}^{2} ] \\ \: using \: the \: same \: identity \: again... \\i.e. = > [x {}^{2} - (y + z) {}^{2} ] \\ = [x + (y + z)] \: [x - (y + z)] \\ ATQ, \: \\ = > [x {}^{2} + (y + z) {}^{2} ] (x + y + z) \\ (x - y - z)$

Answer 2

Answer:

dont know

Step-by-step explanation:

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