Question

It takes 24 hours to fill a swimming pool using two pipes. If the pipe of larger diameter is used for 8 hours and the pipe of the smaller diameter is used for 18 hours. Only half of the pool is filled . How long would each pipe take to fill the swimming pool ? ( please solve the problem, I will mark you the brainliest!)

Answer 1

Answer:

40 hrs

Step-by-step explanation:

It takes 24 hours to fill a swimming pool using two pipes. If the pipe of larger diameter is used for 8 hours and the pipe of the smaller diameter is used for 18 hours. Only half of the pool is filled. How long would each pipe take to fill the swimming pool.

Let A and B be two pipes.

So in 1 hour quantity of water filled by pipe A is 1/A and that of pipe B is 1/B. The quantity of water filled by both pipes in one hour is 1/A + 1/B

It takes 24 hours by pipes to fill the pool

So 1/A + 1/B = 1/24------------(1)

The quantity of water filled in 8 hours by pipe A = 8/A

The quantity of water filled in 18 hours by pipe B = 18/B

Given in the question half is filled s

8/A + 18/B = 1/2-------------(2)

From (1) and (2) we have,

x + y = 1/24-------------(3)

8 x + 18 y = 1/2----------(4)

Multiply eqn (3) by 8 and eqn (4) by 1

8 x + 8 y = 1/3

8 x + 18 y = 1/2

Subtracting we get

- 10 y = - 1/6

y = 1/60

So we have B = 60

The second pipe alone fills in 60 hours

Substituting y = 1/60 in eqn (3) ,

x + 1/60 = 1/24

120 x = 3  

x = 3/120 = 1/40

So A = 40 hours

So it will take 40 hours , if the first pipe alone fills the pool.

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please mark as the brainliest answer.

Answer 2

Answer:bigger pipe-32 , smaller pipe-72

Step-by-step explanation:it takes 8 hours for bigger pipe + 18 hours of smaller pipe to fill half tank

Means it take 8 hours to fill 1/4 tank for bigger pipe

So it will take 8×4=32 hours to fill full yank from bigger pipe

It takes 18 hours for smaller pipe to fill 1/4 tank

So it ill take 18×4=72 hours to fill full tank