Question

It tan2A=cot(A=18°), where 2A is an acute angle,find the value of A.

Answer 1

tan2A = cot( A - 18 )

=> cot( 90 - 2A ) = cot( A - 18 )

=> 90 - 2A = A - 18

=> 108 = 3A

=> 36 = A





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Answer 2

Hey

Here is your answer,

Tan2A = cot (A-18)
Cot (90-2A) = cot (A-18)
90-2A = A-18
2A+A = 90+18
3A = 108
A = 108/3
A = 36

Hope it helps you!