Question

It the ammeter reading is 10A & power
dissipited across resistor R is 100w. find the
equivalent resistance of the combination
across AB​

Answer 1

Answer:

1 ohm

Explanation:

P = V x i

100 =V × 10

V= 10 v

V = i x R

10= 10 ×R

R = 1 ohm

Answer 2

CURRENT. =10A

POWER.= 100W

P= I²R

100/(10)²=R

R=1 ohm

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