it the mass of the moving object is decreased 1/4 of its mass and its velocity is increased to twose ots previous velocity , waht will be the kinetic energy of the object
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let the original mass be m and velocity be v
so,
KE1=1/2×mv²
now
m=m/4
v=2v
so,
KE2=1/2×(m/4)×(2v)²=1/2×m/4×4v²=1/2×mv²
so,
there is no change in the kinetic energy.
so,
KE1=1/2×mv²
now
m=m/4
v=2v
so,
KE2=1/2×(m/4)×(2v)²=1/2×m/4×4v²=1/2×mv²
so,
there is no change in the kinetic energy.
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