Question

It then tud the value of x All 01 G16 IS​

Answer 1

Answer:

14 (option A)

Step-by-step explanation:

We know that $(a-b)^{3} = a^3 - b^3 -3ab(a-b)$

Here a = x and b = $\frac{1}{x}$

So,

$(x - \frac{1}{x}) ^{3} = x^3 - \frac{1}{x^3} -3x\frac{1}{x} (x - \frac{1}{x})$

=> $2^3 = x^3 - \frac{1}{x^3} -3*2$

=> 8 = $x^3 - \frac{1}{x^3} -6$

=> $x^3 - \frac{1}{x^3} = 8 + 6 = 14$