It took 10 joules to push a chair 2 meters across the floor. With what force was the chair pushed?
Answers
Answer:
5N.
Explanation:
Given:
Work Done(W)=10J.
and, Displacement(x)=2m.
To Find:
Force(F)=?
We know that:
W=Fxcos(@)
[Here direction of displacement of the chair is in direction of force applied]
so, @=0°
Now: W=Fxcos(0°)
or W=Fx (since cos(0°)=1)
or 10J=F×2m
or F×2m=10J
or F=(10/2)J/m
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or |F=5N|
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Answer:
Answer:
5N.
Explanation:
Given:
Work Done(W)=10J.
and, Displacement(x)=2m.
To Find:
Force(F)=?
We know that:
W=Fxcos(@)
[Here direction of displacement of the chair is in direction of force applied]
so, @=0°
Now: W=Fxcos(0°)
or W=Fx (since cos(0°)=1)
or 10J=F×2m
or F×2m=10J
or F=(10/2)J/m
======
or |F=5N|
======
Explanation:
Hope this answer will help you.