Question

It X^x + Y^y = 31, then find value of : (x + y)​

Answer 1

Answer:

x=2 , y= 3

(x+y) = 2+3 =5

Step-by-step explanation:

Here, the number and it's power are the same. So, possible numbers : 1^1=1,2^2=4 and3^3=27. Now plug in the values to check which pair suits the equation. You can easily see that2^2+3^3=31. Thus you have x=2,y=3.