It z=3.5i show that
SoT z3_102²+582-136=0
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Answer:
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Step-by-step explanation:
z=3−5i⇒∣z∣
2
=3
2
+5
2
=34
Multiplying the equation throughout with
z
ˉ
,
∣z∣
2
z
2
−10∣z∣
2
z+58∣z∣
2
−136
z
ˉ
=0
Dividing throughout with 34,
z
2
−10z−4
z
ˉ
+58=0
So, z
2
−10z−4
z
ˉ
+58=0⇔z
3
−10z
2
+58z−136=0
ie, proving z
2
−10z−4
z
ˉ
+58=0 proves z
3
−10z
2
+58z−136=0
⇒(3−5i)(3−5i−10)−4(3+5i)+58=−((21+25)+(15−35)i)+(46−20i)=0
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