Question

ita Triangle ABC A=(3, 2, B= (1,4)
and the midpoint of Ac is (2,5), then
midpont of Bc is​

Answer 1

Answer:

Hey mate here is your answer.//

Step-by-step explanation:

The midpoint of BC is (1,6) .

Explanation:

The midpoint of a line joining points (a,b) and (c,d) =(a+b/2,c+d/2),

Given : In a triangle ABC,if A=(3,2), B=(1,4), and the mid point of AC is (2,5).

Let the coordinates of point C=(x,y).

Then , the midpoint of AC will be:

(3+x/2,2+y/2)=(2,5),

3+x/2=2,2+y/2=5,

3+x=2(2),2+y=2(5),

3+x=4,2+y.=10,

x=1,y=8.

∴ coordinates of point C=(1,8)

Then , the midpoint of BC will be

(1+1/2,1+8/2)=(1,6).

Hence, the midpoint of BC = (1,6).

Hope it helps you.//✔✔✔

Please do mark me as Brainliest.//

Answer 2

Answer:

D(2,5) is mid-point of AC

so using mid-point formula

2

x+3

​  

=2

x+3=4

x=1

2

y+2

​  

=5

y+2=10

y=8

∴(x,y)=(1,8)

Let p(x  

1

​  

,y  

1

​  

) be mid-point of BC

by using mid-point formula

x  

1

​  

=  

2

1+1

​  

=  

2

2

​  

=1

y  

1

​  

=  

2

8+4

​  

=  

2

12

​  

=6

p(x  

1

​  

,y  

1

​  

)=(1,6)