Question

its.
7. Find the zeros of the quadratic polynomial (x²-5) and verify the
relation between the zeros and the coefficients.
8. Find the zeros of the​

Answer 1

Answer:

answer is $\sqrt{5}$ and -$\sqrt{5}$

Step-by-step explanation:

$(x^{2}-5)$=0

     $x^{2}$=5

     x=±$\sqrt{5}$

so the zeroes are $\sqrt{5}$ and -$\sqrt{5}$

from the polynomial a=1 b=0 c=-5

so sum of zeroes:

    $\sqrt{5}+(-\sqrt{5})$=-$\frac{-0}{1}$

                 0=0

product of roots:

        $\sqrt{5}$×$(-\sqrt{5})$=$\frac{-5}{1}$

                -5=-5

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