its a velocity -time graph..........find the acceleration between 2 to 6 seconds
Attachments:
nikkinikki:
Is v given for the pointwhen t=6
no
jitna figure me bana h utna hi dia hua h
Ok let me try
plz if u can answer this question tell me soon
Answers
Answered by
2
Taking 1 ruled line of your page as 2 m/sec (as you have taken)
Between t = 2 secs to t = 6 secs, (total time duration = 4 secs)
u ( Initial Velocity ) = 4 m/sec
v (Final Velocity) = -6 m/sec
a = (v-u) / t {you can also find out by taking slope of graph}
a = { -6 - 4 } / 4
a = -10 / 4
a = -5 / 2
a= - 2.5 m/sec square
=> Acceleration = -2.5 m/sec square
HOPE IT HELPS :):):):)
MARK AS BRAINLIEST
Between t = 2 secs to t = 6 secs, (total time duration = 4 secs)
u ( Initial Velocity ) = 4 m/sec
v (Final Velocity) = -6 m/sec
a = (v-u) / t {you can also find out by taking slope of graph}
a = { -6 - 4 } / 4
a = -10 / 4
a = -5 / 2
a= - 2.5 m/sec square
=> Acceleration = -2.5 m/sec square
HOPE IT HELPS :):):):)
MARK AS BRAINLIEST
thanku soo much for helping me
mark as brainliest
UR WELCOME
why the initial velocity is 6 m/ s..
because final velocity is 6
that's y
initial velocity is 4 m/s
final is -6 m/s
okk thanku
Answered by
1
Take u=4 initial velocity
v=-6 final velocity
t=2 to 6 seconds between so t= 4 seconds
a=(v-u) /t
a=(-6-4) /4
a=(-10) /4
a=-10/4
a=-5/2
a=-2.5m/sec
I hope it will help for u ☺.
v=-6 final velocity
t=2 to 6 seconds between so t= 4 seconds
a=(v-u) /t
a=(-6-4) /4
a=(-10) /4
a=-10/4
a=-5/2
a=-2.5m/sec
I hope it will help for u ☺.
thanku soo much for ur help
mark it as brainliest
why
what y
Similar questions