its urgent
if x plus y = 4 then find the value of x^3 + y^3 + 12xy -64
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If x+y=4 then x=4-y
(4-y)^3+y^3 + 12(4-y)y -64
64-y^3-3×16×y+3×4×y^2+y^3+48y-12y^2-64
=0
(4-y)^3+y^3 + 12(4-y)y -64
64-y^3-3×16×y+3×4×y^2+y^3+48y-12y^2-64
=0
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