Question

IUPAC name and oxidation no. of [Pt(NH3)3(NO)Cl2]Br2

Answer 1

Answer:

Triammine nitro dichloro platinum (V) bromide

Explanation:

Let the oxidation state of pt is x

x+0+(-1)+2(-1)+2(-1)=0

x-1-2-2=0

x-5=0

x=+5

Answer 2

IUPAC name and oxidation no. of $[Pt(NH_3)_3(NO)Cl_2]Br_2$ is platinum triaaminedichloronitrosyl platinum (IV) bromide and +4 respectively

Explanation:

Rules for naming of the coordination compounds :

a) The ligands are named first then metal.

b) The charge of metal indicated with the Roman numerals and enclosed in the parenthesis after metal name.

c) The ligands are named in alphabetical order before the metal ion.

d) Ligands that include a numerical prefix in the name use the prefixes bis for 2, tris for 3, or tetrakis for 4 to indicate their number.

e) If the complex ion is an anion, we drop the ending of the metal name and add –ate.

In the given coordination compound, Pt is the platinum metal, $NH_3$ , $NO$ and  $Cl$ are the ligands named as ammine, nitrosyl and chloro.

The charge on $[Pt(NH_3)_3(NO)Cl_2]$ is +2. Ammine is neutral, chloro is having an oxidation state of -1 and nitrosyl is having an oxidation state of 0

x+3(0)+1(0)+2(-1)=+2

x= +4

Hence, the IUPAC name of $[Pt(NH_3)_3(NO)Cl_2]Br_2$ is platinum triaaminedichloronitrosyl platinum (IV) bromide

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