Question

iupac name of C*H_{3} - CH - C*H_{3} C_{2}*H_{5} * C_{2} * H_{5}​

Answer 1

Answer:

iupac name of C*H_{3} - CH - C*H_{3} C_{2}*H_{5} * C_{2} * H_{5}

Explanation:

Carboxylic carbon is numbered as 1 as per the priority rule.Consider the longest carbon chain, at C-2 and C-4, methyl group is present and total 6 carbon atoms are present in longest carbon chain, hence name is 2,4-dimethyl hexanoic acid

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Answer 2

Answer:

The IUPAC name of the given compound is 2-ethyl-2-methyl butane.

Explanation:

• The IUPAC nomenclature is a method to name organic compounds as suggested by the International Union of Pure and Applied Chemistry.
• According to the rules of IUPAC nomenclature, the first step is to find the longest carbon chain.
• In the given compound, the longest continuous carbon chain is of four carbons. This implies that the parent alkane is butane.
• One of the four carbons has two branches which are methyl and ethyl. So, we number the parent carbon chain in such a way that this carbon has the least numbering, i.e., starting from the left so the branched carbon will be numbered 2.
• The two groups on the second carbon are the methyl group and the ethyl group.
• As per the IUPAC rules, the nomenclature has to be in alphabetical order. Therefore, among the two branched groups, ethyl will be written first and then methyl.
• The two groups will be separated by a hyphen (-) from the number of the carbon.
• The branching along with the carbon number is to be mentioned first before writing the name of the parent alkane.

Therefore, 2-ethyl-2-methyl butane is the IUPAC name of the compound.

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