Math, asked by vaishnavipawar9, 6 months ago

iv) (2+i) / (3-i)(1+2i)​

Answers

Answered by lokeshdusane5
10

Answer:

-1/10+3i/10

Step-by-step explanation:

(2+i)/(3-i)(1-2i)=(2+i)/3-6i-i+2i²

=(2+i)/3-7i+2(-1)

=(2+i)/3-7i-2

=(2+i)/(1-7i)

=(2+i)/(1-7i)*(1+7i)/(1+7i)

=(2+14i+i+7i²)/1+7i-7i-49i²)

=(2+15i-7)/(1+49)

=-5+15i/50

=-5/50+15i/50

=-1/10+3i/10

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