Question

இருபடி சமன்பாட்டை தீர்க்க

"(iv) " 36y^2-12ay+(a^2-b^2 )=0

Answer 1

$y=\frac{(a+b)}{6}$ ,  $y=\frac{(a-b)}{6}$

விளக்கம்:

$36 y^{2}-12 a y+\left(a^{2}-b^{2}\right)=0$

$a=36, b=-12 a, c=a^{2}-b^2$

$y=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$=\frac{-(-12 a) \pm \sqrt{(-12 a)^{2}-4(36)\left(a^{2}-b^{2}\right)}}{2(36)}$

$=\frac{12 a \pm \sqrt{144 b^{2}}}{72}$

$=\frac{12 a \pm 12 b}{72}$

$y=\frac{12 a+12 b}{72}$

$=\frac{12(a+b)}{72}$

$y=\frac{(a+b)}{6}$

$y=\frac{12 a-12 b}{72}$

$y=\frac{12(a-b)}{72}$

$y=\frac{(a-b)}{6}$

$y=\frac{(a+b)}{6}$ ,  $y=\frac{(a-b)}{6}$

Answer 2

Answer:

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