Question

இருபடி சமன்பாட்டை தீர்க்க


2x^2-5x+2=0

Answer 1

Explanation:

REFER TO THE ATTACHMENT

YOUR QUESTION

=>SOLVE THE QUADRATIC EQUATION 2x²-5x+2=0

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Answer 2

$x=2$  ,  $x=1 / 2$

விளக்கம்:

$2 x^{2}-5 x+2=0$

$a=2, b=-5, c=2$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

$=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(2)(2)}}{2(2)}$

$=\frac{5 \pm \sqrt{25-16}}{4}$

$=\frac{5 \pm \sqrt{9}}{4}$

$=\frac{5 \pm 3}{4}$

$x=\frac{5+3}{4}$      

$x=\frac{8}{4}$

$x=2$

$x=\frac{5-3}{4}$

$x=\frac{2}{4}$

$x=1 / 2$

$x=2$  ,  $x=1 / 2$